Tentukan nilai a agar garis – garis 2x – y = 3 dan x + ay = 8
a. saling tegak lurus
b. saling sejajar
a. saling tegak lurus
b. saling sejajar
Materi : Persamaan Garis Lurus
[ 2x - y = 3 ] → ( y = 2x - 3 ) { m = 2 }
[ x + ay = 8 ] → ( ay = - x + 8 )
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Bagian A ( saling sejajar )
ay = -x + 8
y = -x/a + 8/a
[ m = mx/a ]
2 = -1/a
2a = -1
{ a = -½ }
Bagian B ( Tegak Lurus )
[ -1/m = mx/a ]
-½ = -1/a
( -½ )a = -1
a = -1 × -½
{ a = ½ }
Semoga bisa membantu
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